2(x+5)-8x=3(x+2)+x

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Solution for 2(x+5)-8x=3(x+2)+x equation: 



2(x+5)-8x=3(x+2)+x

We move all terms to the left:

2(x+5)-8x-(3(x+2)+x)=0

We add all the numbers together, and all the variables

-8x+2(x+5)-(3(x+2)+x)=0

We multiply parentheses

-8x+2x-(3(x+2)+x)+10=0



We calculate terms in parentheses: -(3(x+2)+x), so:

3(x+2)+x

We add all the numbers together, and all the variables

x+3(x+2)

We multiply parentheses

x+3x+6

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

-6x-(4x+6)+10=0

We get rid of parentheses

-6x-4x-6+10=0

We add all the numbers together, and all the variables

-10x+4=0

We move all terms containing x to the left, all other terms to the right

-10x=-4

x=-4/-10

x=2/5

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