2(x+5)4x+8=16

Solution for 2(x+5)4x+8=16 equation:

2(x+5)4x+8=16

We move all terms to the left:

2(x+5)4x+8-(16)=0

We add all the numbers together, and all the variables

2(x+5)4x-8=0

We multiply parentheses

8x^2+40x-8=0

a = 8; b = 40; c = -8;
Δ = b2-4ac
Δ = 402-4·8·(-8)
Δ = 1856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1856}=\sqrt{64*29}=\sqrt{64}*\sqrt{29}=8\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-8\sqrt{29}}{2*8}=\frac{-40-8\sqrt{29}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+8\sqrt{29}}{2*8}=\frac{-40+8\sqrt{29}}{16}
$