2(x+5)=-4(3x-4)+6x

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Solution for 2(x+5)=-4(3x-4)+6x equation: 



2(x+5)=-4(3x-4)+6x

We move all terms to the left:

2(x+5)-(-4(3x-4)+6x)=0

We multiply parentheses

2x-(-4(3x-4)+6x)+10=0



We calculate terms in parentheses: -(-4(3x-4)+6x), so:

-4(3x-4)+6x

We add all the numbers together, and all the variables

6x-4(3x-4)

We multiply parentheses

6x-12x+16

We add all the numbers together, and all the variables

-6x+16

Back to the equation:

-(-6x+16)



We get rid of parentheses

2x+6x-16+10=0

We add all the numbers together, and all the variables

8x-6=0

We move all terms containing x to the left, all other terms to the right

8x=6

x=6/8

x=3/4

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