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2(x+5)=1/2(x-4)
We move all terms to the left:
2(x+5)-(1/2(x-4))=0
Domain of the equation: 2(x-4))!=0We multiply parentheses
x∈R
2x-(1/2(x-4))+10=0
We multiply all the terms by the denominator
2x*2(x-4))-(1+10*2(x-4))=0
Wy multiply elements
4x^2(x+20x(x=0
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