2(x+5)=2x+4x+22(x+5)=2x+4x+2x=

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Solution for 2(x+5)=2x+4x+22(x+5)=2x+4x+2x= equation: 



2(x+5)=2x+4x+22(x+5)=2x+4x+2x=

We move all terms to the left:

2(x+5)-(2x+4x+22(x+5))=0

We multiply parentheses

2x-(2x+4x+22(x+5))+10=0



We calculate terms in parentheses: -(2x+4x+22(x+5)), so:

2x+4x+22(x+5)

We add all the numbers together, and all the variables

6x+22(x+5)

We multiply parentheses

6x+22x+110

We add all the numbers together, and all the variables

28x+110

Back to the equation:

-(28x+110)



We get rid of parentheses

2x-28x-110+10=0

We add all the numbers together, and all the variables

-26x-100=0

We move all terms containing x to the left, all other terms to the right

-26x=100

x=100/-26

x=-3+11/13

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