2(x+5)=3(x+2)-4(x-2)

Solution for 2(x+5)=3(x+2)-4(x-2) equation:

2(x+5)=3(x+2)-4(x-2)

We move all terms to the left:

2(x+5)-(3(x+2)-4(x-2))=0

We multiply parentheses

2x-(3(x+2)-4(x-2))+10=0


We calculate terms in parentheses: -(3(x+2)-4(x-2)), so:

3(x+2)-4(x-2)

We multiply parentheses

3x-4x+6+8

We add all the numbers together, and all the variables

-1x+14

Back to the equation:

-(-1x+14)


We get rid of parentheses

2x+1x-14+10=0

We add all the numbers together, and all the variables

3x-4=0

We move all terms containing x to the left, all other terms to the right

3x=4

x=4/3

x=1+1/3