2(x+5)=3(x-2)=7

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Solution for 2(x+5)=3(x-2)=7 equation: 



2(x+5)=3(x-2)=7

We move all terms to the left:

2(x+5)-(3(x-2))=0

We multiply parentheses

2x-(3(x-2))+10=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

2x-3x+6+10=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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