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2(x+6)-12=(x-6)+12
We move all terms to the left:
2(x+6)-12-((x-6)+12)=0
We multiply parentheses
2x-((x-6)+12)+12-12=0
We calculate terms in parentheses: -((x-6)+12), so:We add all the numbers together, and all the variables
(x-6)+12
We get rid of parentheses
x-6+12
We add all the numbers together, and all the variables
x+6
Back to the equation:
-(x+6)
2x-(x+6)=0
We get rid of parentheses
2x-x-6=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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