2(x+7)-1=(8x/4)+13

Solution for 2(x+7)-1=(8x/4)+13 equation:

2(x+7)-1=(8x/4)+13

We move all terms to the left:

2(x+7)-1-((8x/4)+13)=0

We add all the numbers together, and all the variables

2(x+7)-((+8x/4)+13)-1=0

We multiply parentheses

2x-((+8x/4)+13)+14-1=0

We multiply all the terms by the denominator


2x*4)+13)-((+8x+14*4)+13)-1*4)+13)=0

We add all the numbers together, and all the variables

2x*4)+13)-((8x+56)+13)-1*4)+13)=0

We add all the numbers together, and all the variables

2x*4)+13)-((8x=0

Wy multiply elements

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$