2(x+7)=(x+3)+(4x-2)

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Solution for 2(x+7)=(x+3)+(4x-2) equation: 



2(x+7)=(x+3)+(4x-2)

We move all terms to the left:

2(x+7)-((x+3)+(4x-2))=0

We multiply parentheses

2x-((x+3)+(4x-2))+14=0



We calculate terms in parentheses: -((x+3)+(4x-2)), so:

(x+3)+(4x-2)

We get rid of parentheses

x+4x+3-2

We add all the numbers together, and all the variables

5x+1

Back to the equation:

-(5x+1)



We get rid of parentheses

2x-5x-1+14=0

We add all the numbers together, and all the variables

-3x+13=0

We move all terms containing x to the left, all other terms to the right

-3x=-13

x=-13/-3

x=4+1/3

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