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2(x+9)5x=7x-18
We move all terms to the left:
2(x+9)5x-(7x-18)=0
We multiply parentheses
10x^2+90x-(7x-18)=0
We get rid of parentheses
10x^2+90x-7x+18=0
We add all the numbers together, and all the variables
10x^2+83x+18=0
a = 10; b = 83; c = +18;
Δ = b2-4ac
Δ = 832-4·10·18
Δ = 6169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(83)-\sqrt{6169}}{2*10}=\frac{-83-\sqrt{6169}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(83)+\sqrt{6169}}{2*10}=\frac{-83+\sqrt{6169}}{20} $
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