2(x+x-4)+3=3(x+1)+1

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Solution for 2(x+x-4)+3=3(x+1)+1 equation:



2(x+x-4)+3=3(x+1)+1
We move all terms to the left:
2(x+x-4)+3-(3(x+1)+1)=0
We add all the numbers together, and all the variables
2(2x-4)-(3(x+1)+1)+3=0
We multiply parentheses
4x-(3(x+1)+1)-8+3=0
We calculate terms in parentheses: -(3(x+1)+1), so:
3(x+1)+1
We multiply parentheses
3x+3+1
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
We add all the numbers together, and all the variables
4x-(3x+4)-5=0
We get rid of parentheses
4x-3x-4-5=0
We add all the numbers together, and all the variables
x-9=0
We move all terms containing x to the left, all other terms to the right
x=9

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