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2(x-(4x+13)+3)=2(x+10)
We move all terms to the left:
2(x-(4x+13)+3)-(2(x+10))=0
We calculate terms in parentheses: -(2(x+10)), so:We get rid of parentheses
2(x+10)
We multiply parentheses
2x+20
Back to the equation:
-(2x+20)
2(x-(4x+13)+3)-2x-20=0
We add all the numbers together, and all the variables
-2x+2(x-(4x+13)+3)-20=0
We move all terms containing x to the left, all other terms to the right
-2x+2(x-(4x+13)+3)=20
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