2(x-1)+12=3(x+2)-2

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Solution for 2(x-1)+12=3(x+2)-2 equation: 



2(x-1)+12=3(x+2)-2

We move all terms to the left:

2(x-1)+12-(3(x+2)-2)=0

We multiply parentheses

2x-(3(x+2)-2)-2+12=0



We calculate terms in parentheses: -(3(x+2)-2), so:

3(x+2)-2

We multiply parentheses

3x+6-2

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We add all the numbers together, and all the variables

2x-(3x+4)+10=0

We get rid of parentheses

2x-3x-4+10=0

We add all the numbers together, and all the variables

-1x+6=0

We move all terms containing x to the left, all other terms to the right

-x=-6

x=-6/-1

x=+6

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