2(x-1)+3(x-2)+4(x-3)=3(x-1)

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Solution for 2(x-1)+3(x-2)+4(x-3)=3(x-1) equation: 



2(x-1)+3(x-2)+4(x-3)=3(x-1)

We move all terms to the left:

2(x-1)+3(x-2)+4(x-3)-(3(x-1))=0

We multiply parentheses

2x+3x+4x-(3(x-1))-2-6-12=0



We calculate terms in parentheses: -(3(x-1)), so:

3(x-1)

We multiply parentheses

3x-3

Back to the equation:

-(3x-3)



We add all the numbers together, and all the variables

9x-(3x-3)-20=0

We get rid of parentheses

9x-3x+3-20=0

We add all the numbers together, and all the variables

6x-17=0

We move all terms containing x to the left, all other terms to the right

6x=17

x=17/6

x=2+5/6

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