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2(x-1)+3=3x-(x+4)
We move all terms to the left:
2(x-1)+3-(3x-(x+4))=0
We multiply parentheses
2x-(3x-(x+4))-2+3=0
We calculate terms in parentheses: -(3x-(x+4)), so:We add all the numbers together, and all the variables
3x-(x+4)
We get rid of parentheses
3x-x-4
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
2x-(2x-4)+1=0
We get rid of parentheses
2x-2x+4+1=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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