2(x-1)+3=8(X+2)

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Solution for 2(x-1)+3=8(X+2) equation: 



2(x-1)+3=8(x+2)

We move all terms to the left:

2(x-1)+3-(8(x+2))=0

We multiply parentheses

2x-(8(x+2))-2+3=0



We calculate terms in parentheses: -(8(x+2)), so:

8(x+2)

We multiply parentheses

8x+16

Back to the equation:

-(8x+16)



We add all the numbers together, and all the variables

2x-(8x+16)+1=0

We get rid of parentheses

2x-8x-16+1=0

We add all the numbers together, and all the variables

-6x-15=0

We move all terms containing x to the left, all other terms to the right

-6x=15

x=15/-6

x=-2+1/2

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