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2(x-1)+3=x+-3(x+1)
We move all terms to the left:
2(x-1)+3-(x+-3(x+1))=0
We use the square of the difference formula
2(x-1)-(x-3(x+1))+3=0
We multiply parentheses
2x-(x-3(x+1))-2+3=0
We calculate terms in parentheses: -(x-3(x+1)), so:We add all the numbers together, and all the variables
x-3(x+1)
We multiply parentheses
x-3x-3
We add all the numbers together, and all the variables
-2x-3
Back to the equation:
-(-2x-3)
2x-(-2x-3)+1=0
We get rid of parentheses
2x+2x+3+1=0
We add all the numbers together, and all the variables
4x+4=0
We move all terms containing x to the left, all other terms to the right
4x=-4
x=-4/4
x=-1
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