2(x-1)+4=7(2x+3)-5

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Solution for 2(x-1)+4=7(2x+3)-5 equation: 



2(x-1)+4=7(2x+3)-5

We move all terms to the left:

2(x-1)+4-(7(2x+3)-5)=0

We multiply parentheses

2x-(7(2x+3)-5)-2+4=0



We calculate terms in parentheses: -(7(2x+3)-5), so:

7(2x+3)-5

We multiply parentheses

14x+21-5

We add all the numbers together, and all the variables

14x+16

Back to the equation:

-(14x+16)



We add all the numbers together, and all the variables

2x-(14x+16)+2=0

We get rid of parentheses

2x-14x-16+2=0

We add all the numbers together, and all the variables

-12x-14=0

We move all terms containing x to the left, all other terms to the right

-12x=14

x=14/-12

x=-1+1/6

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