2(x-1)+4x=3(x-2)+13

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Solution for 2(x-1)+4x=3(x-2)+13 equation: 



2(x-1)+4x=3(x-2)+13

We move all terms to the left:

2(x-1)+4x-(3(x-2)+13)=0

We add all the numbers together, and all the variables

4x+2(x-1)-(3(x-2)+13)=0

We multiply parentheses

4x+2x-(3(x-2)+13)-2=0



We calculate terms in parentheses: -(3(x-2)+13), so:

3(x-2)+13

We multiply parentheses

3x-6+13

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We add all the numbers together, and all the variables

6x-(3x+7)-2=0

We get rid of parentheses

6x-3x-7-2=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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