2(x-1)+5(x-1)=7(7x+4)-35

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Solution for 2(x-1)+5(x-1)=7(7x+4)-35 equation: 



2(x-1)+5(x-1)=7(7x+4)-35

We move all terms to the left:

2(x-1)+5(x-1)-(7(7x+4)-35)=0

We multiply parentheses

2x+5x-(7(7x+4)-35)-2-5=0



We calculate terms in parentheses: -(7(7x+4)-35), so:

7(7x+4)-35

We multiply parentheses

49x+28-35

We add all the numbers together, and all the variables

49x-7

Back to the equation:

-(49x-7)



We add all the numbers together, and all the variables

7x-(49x-7)-7=0

We get rid of parentheses

7x-49x+7-7=0

We add all the numbers together, and all the variables

-42x=0

x=0/-42

x=0

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