2(x-1)+5(x-1)=7(x+4)-35

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Solution for 2(x-1)+5(x-1)=7(x+4)-35 equation:



2(x-1)+5(x-1)=7(x+4)-35
We move all terms to the left:
2(x-1)+5(x-1)-(7(x+4)-35)=0
We multiply parentheses
2x+5x-(7(x+4)-35)-2-5=0
We calculate terms in parentheses: -(7(x+4)-35), so:
7(x+4)-35
We multiply parentheses
7x+28-35
We add all the numbers together, and all the variables
7x-7
Back to the equation:
-(7x-7)
We add all the numbers together, and all the variables
7x-(7x-7)-7=0
We get rid of parentheses
7x-7x+7-7=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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