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2(x-1)+5x=2x-(x-5)
We move all terms to the left:
2(x-1)+5x-(2x-(x-5))=0
We add all the numbers together, and all the variables
5x+2(x-1)-(2x-(x-5))=0
We multiply parentheses
5x+2x-(2x-(x-5))-2=0
We calculate terms in parentheses: -(2x-(x-5)), so:We add all the numbers together, and all the variables
2x-(x-5)
We get rid of parentheses
2x-x+5
We add all the numbers together, and all the variables
x+5
Back to the equation:
-(x+5)
7x-(x+5)-2=0
We get rid of parentheses
7x-x-5-2=0
We add all the numbers together, and all the variables
6x-7=0
We move all terms containing x to the left, all other terms to the right
6x=7
x=7/6
x=1+1/6
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