2(x-1)+6(x-3)=3(x-5)

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Solution for 2(x-1)+6(x-3)=3(x-5) equation: 



2(x-1)+6(x-3)=3(x-5)

We move all terms to the left:

2(x-1)+6(x-3)-(3(x-5))=0

We multiply parentheses

2x+6x-(3(x-5))-2-18=0



We calculate terms in parentheses: -(3(x-5)), so:

3(x-5)

We multiply parentheses

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

8x-(3x-15)-20=0

We get rid of parentheses

8x-3x+15-20=0

We add all the numbers together, and all the variables

5x-5=0

We move all terms containing x to the left, all other terms to the right

5x=5

x=5/5

x=1

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