2(x-1)+8=4x-2(-2+x)

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Solution for 2(x-1)+8=4x-2(-2+x) equation: 



2(x-1)+8=4x-2(-2+x)

We move all terms to the left:

2(x-1)+8-(4x-2(-2+x))=0

We add all the numbers together, and all the variables

2(x-1)-(4x-2(x-2))+8=0

We multiply parentheses

2x-(4x-2(x-2))-2+8=0



We calculate terms in parentheses: -(4x-2(x-2)), so:

4x-2(x-2)

We multiply parentheses

4x-2x+4

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

2x-(2x+4)+6=0

We get rid of parentheses

2x-2x-4+6=0

We add all the numbers together, and all the variables

2!=0

There is no solution for this equation

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