2(x-1)-3(x-2)=2(x+5)-4(x-3)

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Solution for 2(x-1)-3(x-2)=2(x+5)-4(x-3) equation: 



2(x-1)-3(x-2)=2(x+5)-4(x-3)

We move all terms to the left:

2(x-1)-3(x-2)-(2(x+5)-4(x-3))=0

We multiply parentheses

2x-3x-(2(x+5)-4(x-3))-2+6=0



We calculate terms in parentheses: -(2(x+5)-4(x-3)), so:

2(x+5)-4(x-3)

We multiply parentheses

2x-4x+10+12

We add all the numbers together, and all the variables

-2x+22

Back to the equation:

-(-2x+22)



We add all the numbers together, and all the variables

-1x-(-2x+22)+4=0

We get rid of parentheses

-1x+2x-22+4=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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