2(x-1)-3(x-2)=4(x-2)=4(x-3)+5(x-4)

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Solution for 2(x-1)-3(x-2)=4(x-2)=4(x-3)+5(x-4) equation: 



2(x-1)-3(x-2)=4(x-2)=4(x-3)+5(x-4)

We move all terms to the left:

2(x-1)-3(x-2)-(4(x-2))=0

We multiply parentheses

2x-3x-(4(x-2))-2+6=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

-1x-(4x-8)+4=0

We get rid of parentheses

-1x-4x+8+4=0

We add all the numbers together, and all the variables

-5x+12=0

We move all terms containing x to the left, all other terms to the right

-5x=-12

x=-12/-5

x=2+2/5

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