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2(x-1)/3=2(x+2)/6
We move all terms to the left:
2(x-1)/3-(2(x+2)/6)=0
We calculate fractions
2x/()+(-(2(x+2)*3)/()=0
We calculate terms in parentheses: +(-(2(x+2)*3)/(), so:We get rid of parentheses
-(2(x+2)*3)/(
We multiply all the terms by the denominator
-(2(x+2)*3)
We calculate terms in parentheses: -(2(x+2)*3), so:We get rid of parentheses
2(x+2)*3
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
-6x-12
Back to the equation:
+(-6x-12)
2x/()-6x-12=0
We multiply all the terms by the denominator
2x-6x*()-12*()=0
We add all the numbers together, and all the variables
2x-6x*()=0
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