2(x-1)/4=2(x+2)/7

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Solution for 2(x-1)/4=2(x+2)/7 equation: 



2(x-1)/4=2(x+2)/7

We move all terms to the left:

2(x-1)/4-(2(x+2)/7)=0

We calculate fractions


2x/()+(-(2(x+2)*4)/()=0



We calculate terms in parentheses: +(-(2(x+2)*4)/(), so:

-(2(x+2)*4)/(

We multiply all the terms by the denominator


-(2(x+2)*4)



We calculate terms in parentheses: -(2(x+2)*4), so:

2(x+2)*4

We multiply parentheses

8x+16

Back to the equation:

-(8x+16)



We get rid of parentheses

-8x-16

Back to the equation:

+(-8x-16)



We get rid of parentheses

2x/()-8x-16=0

We multiply all the terms by the denominator


2x-8x*()-16*()=0

We add all the numbers together, and all the variables

2x-8x*()=0

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