2(x-1)/5=(2x+2)/8

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Solution for 2(x-1)/5=(2x+2)/8 equation: 



2(x-1)/5=(2x+2)/8

We move all terms to the left:

2(x-1)/5-((2x+2)/8)=0

We calculate fractions


2x/()+(-((2x+2)*5)/()=0



We calculate terms in parentheses: +(-((2x+2)*5)/(), so:

-((2x+2)*5)/(

We multiply all the terms by the denominator


-((2x+2)*5)



We calculate terms in parentheses: -((2x+2)*5), so:

(2x+2)*5

We multiply parentheses

10x+10

Back to the equation:

-(10x+10)



We get rid of parentheses

-10x-10

Back to the equation:

+(-10x-10)



We get rid of parentheses

2x/()-10x-10=0

We multiply all the terms by the denominator


2x-10x*()-10*()=0

We add all the numbers together, and all the variables

2x-10x*()=0

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