2(x-1)/5=2(x+1)/7

Solution for 2(x-1)/5=2(x+1)/7 equation:

2(x-1)/5=2(x+1)/7

We move all terms to the left:

2(x-1)/5-(2(x+1)/7)=0

We calculate fractions


2x/()+(-(2(x+1)*5)/()=0


We calculate terms in parentheses: +(-(2(x+1)*5)/(), so:

-(2(x+1)*5)/(

We multiply all the terms by the denominator


-(2(x+1)*5)


We calculate terms in parentheses: -(2(x+1)*5), so:

2(x+1)*5

We multiply parentheses

10x+10

Back to the equation:

-(10x+10)


We get rid of parentheses

-10x-10

Back to the equation:

+(-10x-10)


We get rid of parentheses

2x/()-10x-10=0

We multiply all the terms by the denominator


2x-10x*()-10*()=0

We add all the numbers together, and all the variables

2x-10x*()=0