2(x-1)6=10(1-x)+6

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Solution for 2(x-1)6=10(1-x)+6 equation:



2(x-1)6=10(1-x)+6
We move all terms to the left:
2(x-1)6-(10(1-x)+6)=0
We add all the numbers together, and all the variables
2(x-1)6-(10(-1x+1)+6)=0
We multiply parentheses
12x-(10(-1x+1)+6)-12=0
We calculate terms in parentheses: -(10(-1x+1)+6), so:
10(-1x+1)+6
We multiply parentheses
-10x+10+6
We add all the numbers together, and all the variables
-10x+16
Back to the equation:
-(-10x+16)
We get rid of parentheses
12x+10x-16-12=0
We add all the numbers together, and all the variables
22x-28=0
We move all terms containing x to the left, all other terms to the right
22x=28
x=28/22
x=1+3/11

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