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2(x-1)=5x+2-2(-3x-4)
We move all terms to the left:
2(x-1)-(5x+2-2(-3x-4))=0
We multiply parentheses
2x-(5x+2-2(-3x-4))-2=0
We calculate terms in parentheses: -(5x+2-2(-3x-4)), so:We get rid of parentheses
5x+2-2(-3x-4)
determiningTheFunctionDomain 5x-2(-3x-4)+2
We multiply parentheses
5x+6x+8+2
We add all the numbers together, and all the variables
11x+10
Back to the equation:
-(11x+10)
2x-11x-10-2=0
We add all the numbers together, and all the variables
-9x-12=0
We move all terms containing x to the left, all other terms to the right
-9x=12
x=12/-9
x=-1+1/3
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