2(x-1)=x-4(x-2)

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Solution for 2(x-1)=x-4(x-2) equation:



2(x-1)=x-4(x-2)
We move all terms to the left:
2(x-1)-(x-4(x-2))=0
We multiply parentheses
2x-(x-4(x-2))-2=0
We calculate terms in parentheses: -(x-4(x-2)), so:
x-4(x-2)
We multiply parentheses
x-4x+8
We add all the numbers together, and all the variables
-3x+8
Back to the equation:
-(-3x+8)
We get rid of parentheses
2x+3x-8-2=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2

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