2(x-10)+x+5=4(x+7)+7+x

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Solution for 2(x-10)+x+5=4(x+7)+7+x equation: 



2(x-10)+x+5=4(x+7)+7+x

We move all terms to the left:

2(x-10)+x+5-(4(x+7)+7+x)=0

We add all the numbers together, and all the variables

x+2(x-10)-(4(x+7)+7+x)+5=0

We multiply parentheses

x+2x-(4(x+7)+7+x)-20+5=0



We calculate terms in parentheses: -(4(x+7)+7+x), so:

4(x+7)+7+x

determiningTheFunctionDomain
4(x+7)+x+7

We add all the numbers together, and all the variables

x+4(x+7)+7

We multiply parentheses

x+4x+28+7

We add all the numbers together, and all the variables

5x+35

Back to the equation:

-(5x+35)



We add all the numbers together, and all the variables

3x-(5x+35)-15=0

We get rid of parentheses

3x-5x-35-15=0

We add all the numbers together, and all the variables

-2x-50=0

We move all terms containing x to the left, all other terms to the right

-2x=50

x=50/-2

x=-25

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