2(x-10)=15+4(x-12)

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Solution for 2(x-10)=15+4(x-12) equation: 



2(x-10)=15+4(x-12)

We move all terms to the left:

2(x-10)-(15+4(x-12))=0

We multiply parentheses

2x-(15+4(x-12))-20=0



We calculate terms in parentheses: -(15+4(x-12)), so:

15+4(x-12)

determiningTheFunctionDomain
4(x-12)+15

We multiply parentheses

4x-48+15

We add all the numbers together, and all the variables

4x-33

Back to the equation:

-(4x-33)



We get rid of parentheses

2x-4x+33-20=0

We add all the numbers together, and all the variables

-2x+13=0

We move all terms containing x to the left, all other terms to the right

-2x=-13

x=-13/-2

x=6+1/2

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