2(x-12)+7x=4(x-3)+8

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Solution for 2(x-12)+7x=4(x-3)+8 equation: 



2(x-12)+7x=4(x-3)+8

We move all terms to the left:

2(x-12)+7x-(4(x-3)+8)=0

We add all the numbers together, and all the variables

7x+2(x-12)-(4(x-3)+8)=0

We multiply parentheses

7x+2x-(4(x-3)+8)-24=0



We calculate terms in parentheses: -(4(x-3)+8), so:

4(x-3)+8

We multiply parentheses

4x-12+8

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We add all the numbers together, and all the variables

9x-(4x-4)-24=0

We get rid of parentheses

9x-4x+4-24=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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