2(x-2)(x+2)=40

Solution for 2(x-2)(x+2)=40 equation:

2(x-2)(x+2)=40

We move all terms to the left:

2(x-2)(x+2)-(40)=0

We use the square of the difference formula

x^2-4-40=0

We add all the numbers together, and all the variables

x^2-44=0

a = 1; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·1·(-44)
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{11}}{2*1}=\frac{0-4\sqrt{11}}{2}
=-\frac{4\sqrt{11}}{2}
=-2\sqrt{11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{11}}{2*1}=\frac{0+4\sqrt{11}}{2}
=\frac{4\sqrt{11}}{2}
=2\sqrt{11}
$