2(x-2)+1=2(x+4)+x+13

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Solution for 2(x-2)+1=2(x+4)+x+13 equation:



2(x-2)+1=2(x+4)+x+13
We move all terms to the left:
2(x-2)+1-(2(x+4)+x+13)=0
We multiply parentheses
2x-(2(x+4)+x+13)-4+1=0
We calculate terms in parentheses: -(2(x+4)+x+13), so:
2(x+4)+x+13
We add all the numbers together, and all the variables
x+2(x+4)+13
We multiply parentheses
x+2x+8+13
We add all the numbers together, and all the variables
3x+21
Back to the equation:
-(3x+21)
We add all the numbers together, and all the variables
2x-(3x+21)-3=0
We get rid of parentheses
2x-3x-21-3=0
We add all the numbers together, and all the variables
-1x-24=0
We move all terms containing x to the left, all other terms to the right
-x=24
x=24/-1
x=-24

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