2(x-2)+2(x+4)=(x+3)+(x+4)+(x+5)

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Solution for 2(x-2)+2(x+4)=(x+3)+(x+4)+(x+5) equation:


2(x-2)+2(x+4)=(x+3)+(x+4)+(x+5)

We simplify the equation to the form, which is simple to understand 
2(x-2)+2(x+4)=(x+3)+(x+4)+(x+5)

Reorder the terms in parentheses
+(+2x-4)+2*(x+4)=(x+3)+(x+4)+(x+5)

Remove unnecessary parentheses
+2x-4+2+*(+x+4+)=+(+x+3+)+(+x+4+)+(+x+5+)

Reorder the terms in parentheses
+2x-4+(+2x+8)=(x+3)+(x+4)+(x+5)

Remove unnecessary parentheses
+2x-4+2x+8=+(+x+3+)+(+x+4+)+(+x+5+)

Remove unnecessary parentheses
+2x-4+2x+8=x+3+(x+4)+(x+5)

Remove unnecessary parentheses
+2x-4+2x+8=+x+3+x+4+(+x+5+)

Remove unnecessary parentheses
+2x-4+2x+8=+x+3+x+4+x+5

We move all terms containing x to the left and all other terms to the right. 
+2x+2x-1x-1x-1x=+3+4+5+4-8

We simplify left and right side of the equation. 
+1x=+8

We divide both sides of the equation by 1 to get x. 
x=8

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