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2(x-2)+28=(2x+1)
We move all terms to the left:
2(x-2)+28-((2x+1))=0
We multiply parentheses
2x-((2x+1))-4+28=0
We calculate terms in parentheses: -((2x+1)), so:We add all the numbers together, and all the variables
(2x+1)
We get rid of parentheses
2x+1
Back to the equation:
-(2x+1)
2x-(2x+1)+24=0
We get rid of parentheses
2x-2x-1+24=0
We add all the numbers together, and all the variables
23!=0
There is no solution for this equation
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