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2(x-2)+28=2(x+1)
We move all terms to the left:
2(x-2)+28-(2(x+1))=0
We multiply parentheses
2x-(2(x+1))-4+28=0
We calculate terms in parentheses: -(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
2x-(2x+2)+24=0
We get rid of parentheses
2x-2x-2+24=0
We add all the numbers together, and all the variables
22!=0
There is no solution for this equation
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