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2(x-2)+2=5x-3(1+x)
We move all terms to the left:
2(x-2)+2-(5x-3(1+x))=0
We add all the numbers together, and all the variables
2(x-2)-(5x-3(x+1))+2=0
We multiply parentheses
2x-(5x-3(x+1))-4+2=0
We calculate terms in parentheses: -(5x-3(x+1)), so:We add all the numbers together, and all the variables
5x-3(x+1)
We multiply parentheses
5x-3x-3
We add all the numbers together, and all the variables
2x-3
Back to the equation:
-(2x-3)
2x-(2x-3)-2=0
We get rid of parentheses
2x-2x+3-2=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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