2(x-2)+3(x+3)=2(x+3)-3(x+2)

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Solution for 2(x-2)+3(x+3)=2(x+3)-3(x+2) equation: 



2(x-2)+3(x+3)=2(x+3)-3(x+2)

We move all terms to the left:

2(x-2)+3(x+3)-(2(x+3)-3(x+2))=0

We multiply parentheses

2x+3x-(2(x+3)-3(x+2))-4+9=0



We calculate terms in parentheses: -(2(x+3)-3(x+2)), so:

2(x+3)-3(x+2)

We multiply parentheses

2x-3x+6-6

We add all the numbers together, and all the variables

-x

Back to the equation:

-(-x)



We add all the numbers together, and all the variables

2x+3x-(-1x)-4+9=0

We add all the numbers together, and all the variables

5x-(-1x)+5=0

We get rid of parentheses

5x+1x+5=0

We add all the numbers together, and all the variables

6x+5=0

We move all terms containing x to the left, all other terms to the right

6x=-5

x=-5/6

x=-5/6

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