2(x-2)+3(x-3)=3(x-5)-4(x-8)

Solution for 2(x-2)+3(x-3)=3(x-5)-4(x-8) equation:

2(x-2)+3(x-3)=3(x-5)-4(x-8)

We move all terms to the left:

2(x-2)+3(x-3)-(3(x-5)-4(x-8))=0

We multiply parentheses

2x+3x-(3(x-5)-4(x-8))-4-9=0


We calculate terms in parentheses: -(3(x-5)-4(x-8)), so:

3(x-5)-4(x-8)

We multiply parentheses

3x-4x-15+32

We add all the numbers together, and all the variables

-1x+17

Back to the equation:

-(-1x+17)


We add all the numbers together, and all the variables

5x-(-1x+17)-13=0

We get rid of parentheses

5x+1x-17-13=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5