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2(x-2)+3x=2(x+1)+2+2
We move all terms to the left:
2(x-2)+3x-(2(x+1)+2+2)=0
We add all the numbers together, and all the variables
3x+2(x-2)-(2(x+1)+2+2)=0
We multiply parentheses
3x+2x-(2(x+1)+2+2)-4=0
We calculate terms in parentheses: -(2(x+1)+2+2), so:We add all the numbers together, and all the variables
2(x+1)+2+2
We add all the numbers together, and all the variables
2(x+1)+4
We multiply parentheses
2x+2+4
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
5x-(2x+6)-4=0
We get rid of parentheses
5x-2x-6-4=0
We add all the numbers together, and all the variables
3x-10=0
We move all terms containing x to the left, all other terms to the right
3x=10
x=10/3
x=3+1/3
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