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2(x-2)+5(2-x)=-3(2x+2)
We move all terms to the left:
2(x-2)+5(2-x)-(-3(2x+2))=0
We add all the numbers together, and all the variables
2(x-2)+5(-1x+2)-(-3(2x+2))=0
We multiply parentheses
2x-5x-(-3(2x+2))-4+10=0
We calculate terms in parentheses: -(-3(2x+2)), so:We add all the numbers together, and all the variables
-3(2x+2)
We multiply parentheses
-6x-6
Back to the equation:
-(-6x-6)
-3x-(-6x-6)+6=0
We get rid of parentheses
-3x+6x+6+6=0
We add all the numbers together, and all the variables
3x+12=0
We move all terms containing x to the left, all other terms to the right
3x=-12
x=-12/3
x=-4
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