2(x-2)-3(2x+1)=3(-2x+3)-(x-2)+3

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Solution for 2(x-2)-3(2x+1)=3(-2x+3)-(x-2)+3 equation: 



2(x-2)-3(2x+1)=3(-2x+3)-(x-2)+3

We move all terms to the left:

2(x-2)-3(2x+1)-(3(-2x+3)-(x-2)+3)=0

We multiply parentheses

2x-6x-(3(-2x+3)-(x-2)+3)-4-3=0



We calculate terms in parentheses: -(3(-2x+3)-(x-2)+3), so:

3(-2x+3)-(x-2)+3

We multiply parentheses

-6x-(x-2)+9+3

We get rid of parentheses

-6x-x+2+9+3

We add all the numbers together, and all the variables

-7x+14

Back to the equation:

-(-7x+14)



We add all the numbers together, and all the variables

-4x-(-7x+14)-7=0

We get rid of parentheses

-4x+7x-14-7=0

We add all the numbers together, and all the variables

3x-21=0

We move all terms containing x to the left, all other terms to the right

3x=21

x=21/3

x=7

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