2(x-2)-3(x-3)=4(x-4)-1

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Solution for 2(x-2)-3(x-3)=4(x-4)-1 equation: 



2(x-2)-3(x-3)=4(x-4)-1

We move all terms to the left:

2(x-2)-3(x-3)-(4(x-4)-1)=0

We multiply parentheses

2x-3x-(4(x-4)-1)-4+9=0



We calculate terms in parentheses: -(4(x-4)-1), so:

4(x-4)-1

We multiply parentheses

4x-16-1

We add all the numbers together, and all the variables

4x-17

Back to the equation:

-(4x-17)



We add all the numbers together, and all the variables

-1x-(4x-17)+5=0

We get rid of parentheses

-1x-4x+17+5=0

We add all the numbers together, and all the variables

-5x+22=0

We move all terms containing x to the left, all other terms to the right

-5x=-22

x=-22/-5

x=4+2/5

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