2(x-2)-3(x-3)=5(x-5)+4(x-8)

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Solution for 2(x-2)-3(x-3)=5(x-5)+4(x-8) equation: 



2(x-2)-3(x-3)=5(x-5)+4(x-8)

We move all terms to the left:

2(x-2)-3(x-3)-(5(x-5)+4(x-8))=0

We multiply parentheses

2x-3x-(5(x-5)+4(x-8))-4+9=0



We calculate terms in parentheses: -(5(x-5)+4(x-8)), so:

5(x-5)+4(x-8)

We multiply parentheses

5x+4x-25-32

We add all the numbers together, and all the variables

9x-57

Back to the equation:

-(9x-57)



We add all the numbers together, and all the variables

-1x-(9x-57)+5=0

We get rid of parentheses

-1x-9x+57+5=0

We add all the numbers together, and all the variables

-10x+62=0

We move all terms containing x to the left, all other terms to the right

-10x=-62

x=-62/-10

x=6+1/5

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